ࡱ> [ bjbj hΐΐu&11111$UUUPl U9t"8888888$Z;=81  8119111 j1181 811:=7,7Yw U]!i7 m8909s7R>]!>7>17>,1$ $H 881j9 > : S GIO DC V O TO QUNG NAM PHN PHI CHNG TRNH MN TH DC 37 TUN LP 10 (37 tun/nm hc) (HK I: 19 tun x 2 tit = 38 tit. HK II: 18 tun x 2 tit = 36 tit. C nm: 74 tit) TunTitNi dung11LT1: Gii thiu mc tiu mn hc. Tp luyn TDTT v s dng cc yu t thin nhin  rn luyn sc khe  Lp phiu kho st2LT2: V sinh c nhn, v sinh tp luyn v v sinh mi trng.23C1: K thut di chuyn; Chuyn cu bng mu bn chn4BC1: - T th chun b; Di chuyn (bc thng, bc cho). - Chuyn bng cao tay bng hai tay trc mt. 35C2: - K thut di chuyn. - Chuyn cu bng mu bn chn; Tng  bng cu. 6BC2: - TTCB; Di chuyn (bc thng, bc cho). - Chuyn bng cao bng hai tay trc mt47C3: - Chuyn cu bng mu bn chn. - Tng  bng cu; Gii thiu Lut  cu.8BC3: - Gii thiu mt s im trong lut Bng chuyn. - Chuyn bng cao tay bng hai tay trc mt.59C4: - Chuyn cu bng mu bn chn; Tng  bng cu. - u tp. 10BC4: - Chuyn bng cao tay bng hai tay trc mt; m bng611C5: - KT tng cu nhp 1 v chuyn cu bng mu bn chn. - u tp; - Gii thiu Lut  cu. 12BC5: - Gii thiu m s im trong lut Bng chuyn. - Chuyn bng cao tay bng hai tay trc mt; m bng.713C6 : Kim tra 15 pht K thut tng cu nhp 1 v chuyn cu bng mu bn chn. (1) 14BC6: Pht bng thp tay chnh din; m bng; u tp.815TD1: Bi TDN 9 ng tc dng chung (Nam  N) Hc ng tc t 1 n 2 16BC7: Pht bng thp tay chnh din; m bng; u tp.917TD2: Bi TDN 9 /t chung (Nam - N): n /t t 1 n 2. Hc /t 3 n 418BC8: Pht bng thp tay chnh din; m bng; u tp1019TD3: Bi TDN 9 /t chung (Nam - N): n /t t 1 n 4. Hc /t t 5 n 6. 20BC9: - Chuyn bng cao tay bng hai tay trc mt. - Pht bng thp tay chnh din; - u tp. 1121TD4 : Bi TDN 9 /t chung (Nam - N): n /t t 1 n 6. Hc /t t 7 n 8.22BC10: Kim tra 1tit k thut Chuyn bng cao tay bng hai tay trc mt v m bng, pht bng thp tay chnh din. (2) 1223TD5: Bi TDN 9 /t chung (Nam - N): n /t t 1 n 8. Hc ng tc 9.24CN1: - Bi tp b tr KT chy: Chy BN; Chy nng cao i. - Chy p sau; Chy tng tc 30m.1325TD6: Bi TDN 9 /t chung (Nam - N): n ng tc t 1 n 9.26CN2: Chy tng tc 30m; Chy lp li cc on 20 - 30m.1427TD7: Hon thin Bi TDN 9 ng tc dng chung (Nam - N ). 28CN3: - ng bn p; XPT vi bn p - chy 15m - 20m. - K thut v ch; - Chy lp li cc on 20m - 30m.1529TD8: Kim tra15 pht bi TDN 9 ng tc dng chung(Nam,N). (3) 30CN4: - Chy lp li cc on 30m - 60m. - Tp phi hp 04 giai on KT chy ngn.1631CN5: - Tp phi hp 04 giai on KT chy ngn. - Gii thiu lut in kinh (phn chy ngn). 32B1: Chy v dng t ngt; Dn bng bng lng bn chn.1733CN6: - Hon thin 04 giai on KT chy ngn; - Gii thiu lut in kinh (phn chy ngn).34B2: - Chy v dng t ngt. - Dn bng bng lng bn chn; Chy v bt nhy.1835CN7: n k thut chy ngn 36CN8: Phng php t chc trng ti mn chy ngn. 1937Kim tra hc k I : Chy ngn (c ly 80m - 100m) . (4)382039B3: - Chy v dng t ngt; Chy v bt nhy. - Dn bng bng lng bn chn;  bng bng lng bn chn. - Dng bng bng lng bn chn.40CL1: T th chun b; Cch cm vt, cm cu. CB1: Gii thiu k thut chy bn.2141B4: - Dn bng bng lng bn chn;  bng bng lng bn chn. - Dng bng bng lng bn chn.42CL2: - Gii thiu mt s im trong lut cu lng. - ng tc di chuyn n bc (tin, li) kt hp nh cu thp thun tay CB2: Hc k thut chy trn ng thng (BT1 trang 7) 2243B5: - Gii thiu mt s im trong Lut bng . -  bng bng lng bn chn; Dn bng bng lng bn chn. - Dng bng bng lng bn chn.44CL3: - Gii thiu mt s im trong lut cu lng. - ng tc di chuyn n bc (tin, li) kt hp nh cu thp tri tay. CB3: Luyn tp chy bn (n BT1 trang 7).2345B6: - Gii thiu mt s im trong Lut bng . - Dng bng bng lng bn chn; Nm bin (khng chy ).46CL4: - Gii thiu mt s im trong lut cu lng. - Pht cu cao - su thun tay. CB4: Luyn tp chy bn (Hc KT chy trn ng vng BT3 tr 71).2447B7: - Gii thiu mt s im trong Lut bng . - Dng bng, kt hp  bng bng lng bn chn vo cu mn. - Nm bin (khng chy ). u tp.48CL5: - Gii thiu mt s im trong lut cu lng. - Pht cu cao - su thun tay. CB5: Luyn tp chy bn (Phi hp th trong chy bn).2549B8: - Dng bng kt hp  bng bng lng bn chn. - Nm bin (khng chy ); u tp.50CL6: - Pht cu thp gn - thun tay; u tp. CB6: Luyn tp chy bn (BT2 trang 7).2651B9: - Dng bng kt hp  bng bng lng bn chn. - Nm bin (khng chy ); u tp.52CL7: - Pht cu thp gn - thun tay; u tp. CB7: Luyn tp chy bn (Hc chin thut c bn trong chy bn).2753B10: Kim tra 15 pht KT dng bng kt hp  bng bng lng bn chn vo cu mn (Nam c ly 9m; N 6m - Cu mn: cao 2m, rng 3m); Nm bin (khng chy ). (1) 54CL8: Pht cu cao - su thun tay; thp gn thun tay; u tp. CB8: Luyn tp chy bn (Hin tng cc im v cch khc phc BT 5).2855NC1: - Gii thiu KT nhy cao kiu  nm nghing . - ng ti ch  lng; ng ti ch  lng - xoay mii bn chn. - i mt bc  lng - xoay mii bn chn.56CL9: Phi hp nh cu thp thun tay v tri tay. CB9: Luyn tp chy bn (Bi tp hi t)nh BT8 trang 72).2957NC2: - i mt bc  lng - xoay mii bn chn. -  mt bc - gim nhy  lng; M phng ng tc qua x.58CL10: Kim tra1 tit k thut nh cu thp thun tay v tri tay. (2) CB10: Luyn tp chy bn. (Bi tp hi t)nh BT8 trang 72).3059NC3: -  mt bc - gim nhy  lng; M phng ng tc qua x. - Cch o , iu chnh , xc nh im gim nhy.60CL11: Kim tra 1tit nh cu thp thun tay v tri tay (TT) . (2) CB11: Luyn tp chy bn. (Phng php pht trin sc bn BT6).3161NC4: - Giai on gim nhy - trn khng v tip t. - Giai on chy  - gim nhy - trn khng.62TL1: Kim tra th lc, ni dung: Chy 30m Xut pht cao. CB12: Luyn tp chy bn (Phng php pht trin sc bn BT6).3263NC5: - Chy  (3-5 bc) gim nhy - trn khng v tip t. - Bi tp pht trin sc mnh chn.64CB13: Hon thin KT chy bn. Lut thi u v PP trng ti.3365NC6: - n k thut chy  - gim nhy - trn khng v tip t. - Bi tp pht trin sc mnh chn. - Gii thiu mt s im trong Lut in kinh (phn nhy cao).66CB14: Kim tra 15 pht chy bn (C ly nam 1000m; n 500m). (3)3467NC7: n k thut chy  - gim nhy - trn khng v tip t.68TL2: Kim tra th lc, ni dung: Chy ty sc 5 pht.3569NC8: Hon thin k thut nhy cao kiu  nm nghing .70TL3,4: Kim tra ni dung: Bt xa ti ch, Nm nga gp thn.3671 n KT nhy cao kiu "nm nghing". 72Phng php t chc trng ti mn nhy cao.3773 Kim tra hc k II: Nhy cao kiu"nm nghing" (4)74 LP 11 (37 tun/nm hc) (HK I: 19 tun x 2 tit = 38 tit. HK II: 18 tun x 2 tit = 36 tit. C nm: 74 tit) TunTitNi dung11LT1: - Nguyn tc va sc (khi nim, ni dung, yu cu).  Lp phiu kho st2CL1: - Mt s bi tp k thut; nh cu cao thun tay. - Gii thiu mt s im trong lut cu lng.23LT2: - Nguyn tc h thng (khi nim, ni dung, yu cu) 4CL2: - Mt s bi tp k thut; nh cu cao thun tay. - p cu chnh din; u tp.35CL3: - Mt s bi tp k thut. - nh cu cao thun tay; p cu chnh din. - Gii thiu mt s im trong lut Cu lng; u tp.6BC1: - Chuyn bng cao tay bng hai tay. - m bng; Pht bng thp tay chnh din.47CL4: - nh cu cao thun tay; p cu chnh din. - Mt s bi tp phi hp chin thut; u tp.8BC2: - Chuyn bng cao tay bng hai tay; m bng. - Pht bng thp tay chnh din; Mt s bi tp phi hp.59CL5: - p cu chnh din. - Mt s bi tp phi hp chin thut; u tp10BC3: Mt s bi tp phi hp; Pht bng thp tay nghing mnh. 611CL6: Kim tra 15 pht k thut nh cu cao thun tay. (1)12BC4: Mt s bi tp phi hp; Pht bng thp tay nghing mnh.713TD1: + Bi TDN 9 ng tc N: Hc ng tc t 1 n 2. + Bi TDPTC 50 ng tc Nam: Hc ng tc t 1 n 10.14BC5: Mt s bi tp phi hp; Pht bng thp tay nghing mnh.815TD2: + Bi TDN N : n ng tc 1 n 2. Hc ng tc 3 n 4. + Bi TDPTC Nam: n ng tc t 1-10. Hc ng tc t 11-30 16BC6: Mt s bi tp phi hp; Pht bng thp tay nghing mnh.917TD3: + Bi TDN N: n ng tc 1 n 4. + Bi TDPTC Nam:n ng tc t 1-30. Hcng tc t 31-41 18BC7: - Mt s bi tp phi hp; Pht bng thp tay nghing mnh. - Gii thiu mt s im trong lut bng chuyn.1019TD4: + Bi TDN N: n ng tc t 1 n 4. Hc ng tc t 5 n 6 + Bi TDPTC Nam: n ng tc 1 n 41.20- BC8: - Pht bng thp tay nghing mnh. - Gii thiu mt s im trong lut bng chuyn; u tp.1121TD5 : + Bi TDN N: n ng tc t 1 n 6. Hc ng tc t 7 n 9 + Bi TDPTC Nam:n c tc t 1 n 41 Hc ng tc 42 n 5022BC9: - Chuyn bng cao tay bng hai tay; m bng (vo quy nh); - Pht bng thp tay nghing mnh; u tp.1223TD6: + Bi TDN N: n bi TDN 9 ng tc + Bi TDPTC Nam: n bi TDPTC 50 ng tc.24BC10: Kim tra 1 tit KT pht bng thp tay nghing mnh; K thut Chuyn bng cao tay bng hai tay; m bng. (2)1325TD7: KT 15 pht Bi TDN 9 /t N, Bi TDPTC 50 /t (Nam) (3)26TS1: Gii thiu ni dung chy tip sc: 4 x 100m; - BT b tr k thut.1427TS2: Bi tp b tr k thut. 28NC1: Mt s bi tp b tr v pht trin th lc.1529TS3: Bi tp b tr k thut. 30NC2: Phi hp chy  - gim nhy - trn khng1631TS4: - Bi tp b tr k thut. - Gii thiu mt s im trong Lut in kinh (phn chy TS)32NC3: - Phi hp chy  - gim nhy - trn khng - tip t.1733TS5: - Hon thin k thut chy tip sc (4 x 40m). 34NC4: - Phi hp chy  - gim nhy - trn khng - tip t. - Gii thiu mt s im trong Lut in kinh ( phn nhy cao). 1835TS6: n K thut chy tip sc (4x40m). 36TS7: Phng php t chc trng ti mn chy Tip sc.1937 Kim tra hc k I: K thut chy tip sc 4x 40m (4)382039B1: - Di chuyn khng bng; Dn bng bng lng bn chn. - Dn bng bng m ngoi bn chn.40NC5: - n k thut nhy cao kiu  nm nghing . - Gii thiu mt s im trong Lut in kinh (phn nhy cao). CB1: Luyn tp chy bn.2141B2: -  bng bng mu trong bn chn. - Dn bng bng m ngoi bn chn; Dn bng bng lng bn chn.42NC6: Hon thin k thut nhy cao kiu  nm nghing . CB2: Luyn tp chy bn.2243B3: - Dn bng bng m ngoi bn chn. -  bng bng mu trong bn chn; Dn bng bng lng bn chn.44NC7: Kim tra 15 pht nhy cao kiu  nm nghing . (1) CB3: Luyn tp chy bn.2345B4: - Dn bng bng m ngoi bn chn. -  bng bng mu trong bn chn.46C1: - K thut di chuyn bc lt; Tng  git cu. CB4: Luyn tp chy bn.2447B5: - Bi tp phi hp; u tp.48C2: - K thut di chuyn bc lt; Tng  git cu. - Tng cu nhp 1  tn cng bng mu bn chn. CB5: Luyn tp chy bn.2549B6: - Bi tp phi hp; u tp.50C3: - Tng cu nhp 1  tn cng bng mu bn chn. - Gii thiu mt s im trong Lut  cu. CB6: Luyn tp chy bn.2651B7: - Bi tp phi hp; u tp. - Gii thiu mt s im trong Lut Bng . 52C4: Tng cu nhp 1  tn cng bng mu bn chn; u tp. CB7: Luyn tp chy bn.2753B8:  bng bng mu trong bn chn vo vng trn bn knh 5m t khong cch 15- 20m; u tp.54C5: - Tng cu nhp 1  tn cng bng mu bn chn. - Gii thiu mt s im trong Lut  cu. CB8: Luyn tp chy bn.2855B9:  bng bng mu trong bn chn vo vng trn bn knh 5m t khong cch 15- 20m; u tp.56C6: - Tng  git cu. - Tng cu nhp 1  tn cng bng mu bn chn; u tp. CB9: Luyn tp chy bn.2957B10: Kim tra 1tit KT  bng bng mu trong bn chn. (2)58C7: Hon thin k thut Tng  git cu; Tng cu nhp 1  tn cng bng mu bn chn. CB10: Luyn tp chy bn.3059C8: Kim tra 15 pht KT tng  git cu ( N) - Tng cu nhp 1-  tn cng bng mu bn chn. (Nam) (3)60NX1: - Gii thiu KT nhy xa kiu  n thn  . - Tp m phng ng tc chn gim, chn lng. - Tp gim nhy - trn khng. CB11: Luyn tp chy bn.Gii thiu lut.3161NX2: - Mt s bi tp pht trin th lc. - Phi hp chy  - gim nhy - trn khng.62CB12: Hon thin KT chy bn. Lut v PP trng ti.3263NX3: - Mt s bi tp pht trin th lc. - Phi hp chy  - gim nhy - trn khng. 64CB13 : Kim tra 15 pht chy bn (Nam 1000m, n 500m tnh thi gian) (4)3365NX4: - Mt s bi tp pht trin th lc. - Tp phi hp chy  - gim nhy - trn khng - tip t. - Gii thiu mt s im trong Lut in kinh (phn nhy xa). 66TL1: Kim tra th lc: Chy ty sc 5 pht.3467NX5: - Phi hp chy  - gim nhy - trn khng - tip t. - Gii thiu mt s im trong Lut in kinh (phn nhy xa). 68TL2,3: Kim tra ni dung: Nm nga gp c bng; Bt xa >RT T F J n p FJBD26&((,2246NPjlfz $&hT(hrmH sH h.m hT(hT( hT(hrh.mhr5mH sH h.m5mH sH hT(hr5hT(h x5>*mH sH hT(h x5mH sH C.RT $$Ifa$gdr$a$gdrgd x occT $Ifgdr $$Ifa$gdrkd$$IflF0 (A$ t0*6    44 la D pg[L $Ifgdr $$Ifa$gdr $Ifgdrkd$$Ifl4F0 (A$ t0*6    44 laD F J N pddU $Ifgdr $$Ifa$gdrkdr$$Ifl4F0 ( A$ t0*6    44 la < pg[LL $Ifgdr $$Ifa$gdr $Ifgdrkd-$$Ifl4F0 (A$ t0*6    44 la l pddUU $Ifgdr $$Ifa$gdrkd$$Ifl4F0 ( A$ t0*6    44 lal n p t Dpg[LL $Ifgdr $$Ifa$gdr $Ifgdrkd$$Ifl4F0 (A$ t0*6    44 laDFJNpddUU $Ifgdr $$Ifa$gdrkd^$$Ifl4F0 ( A$ t0*6    44 lapg[LL $Ifgdr $$Ifa$gdr $Ifgdrkd$$Ifl4F0 (A$ t0*6    44 latpddUU $Ifgdr $$Ifa$gdrkd$$Ifl4F0 ( A$ t0*6    44 la0pg[L $Ifgdr $$Ifa$gdr $Ifgdrkd$$Ifl4F0 (A$ t0*6    44 la026<$pddUU $Ifgdr $$Ifa$gdrkdJ$$Ifl4F0 ( A$ t0*6    44 la$&(.&pg[LL $Ifgdr $$Ifa$gdr $Ifgdrkd$$Ifl4F0 (A$ t0*6    44 la&(,22pddUU $Ifgdr $$Ifa$gdrkd$$Ifl4F0 ( A$ t0*6    44 la246<pg[L $Ifgdr $$Ifa$gdr $Ifgdrkd{ $$Ifl4F0 (A$ t0*6    44 laLpddU $Ifgdr $$Ifa$gdrkd6 $$Ifl4F0 ( A$ t0*6    44 laLNPVpg[L $Ifgdr $$Ifa$gdr $Ifgdrkd $$Ifl4F0 (A$ t0*6    44 lahpddU $Ifgdr $$Ifa$gdrkd $$Ifl4F0 ( A$ t0*6    44 lahjlrpg[L $Ifgdr $$Ifa$gdr $Ifgdrkdg $$Ifl4F0 (A$ t0*6    44 lapddU $Ifgdr $$Ifa$gdrkd" $$Ifl4F0 ( A$ t0*6    44 laxpg[LL $Ifgdr $$Ifa$gdr $Ifgdrkd $$Ifl4F0 (A$ t0*6    44 laxz"pddU $Ifgdr $$Ifa$gdrkd$$Ifl4F0 ( A$ t0*6    44 la"$&,pg[LL $Ifgdr $$Ifa$gdr $IfgdrkdS$$Ifl4F0 (A$ t0*6    44 la&,j68&,f j l ,!2! 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laj%l%n%t%v%pg[L $Ifgdr $$Ifa$gdr $Ifgdrkd $$Ifl4F0 (A$ t0*6    44 lav%x%~%%%n&&pddUUU $Ifgdr $$Ifa$gdrkd$$Ifl4F0 ( A $ t0*6    44 la&&&&('p'pg[LL $Ifgdr $$Ifa$gdr $Ifgdrkd$$Ifl4F0 (A$ t0*6    44 lap'r'x'~''R(nbbSS $Ifgdr $$Ifa$gdrkdF$$Ifl4jF0 ( A$ t0*6    44 laR(T(V(\((h))pg[LLL $Ifgdr $$Ifa$gdr $Ifgdrkd$$Ifl4F0 (A$ t0*6    44 la))))X**6+pddUUU $Ifgdr $$Ifa$gdrkd$$Ifl4F0 ( A$ t0*6    44 la6+8+:+@++4,j,,pg[LLLL $Ifgdr $$Ifa$gdr $Ifgdrkd{$$Ifl4F0 (A$ t0*6    44 la,,,,4--pddUU $Ifgdr $$Ifa$gdrkd6 $$Ifl4F0 ( A$ t0*6    44 la----.../pg[LLL $Ifgdr $$Ifa$gdr $Ifgdrkd $$Ifl4F0 (A$ t0*6    44 la// //v/0f0pddUUU $Ifgdr $$Ifa$gdrkd!$$Ifl4F0 ( A$ t0*6    44 laf0h0j0p00(11pg[LLL $Ifgdr $$Ifa$gdr $Ifgdrkdg"$$Ifl4F0 (A$ t0*6    44 la11112p2nbbSS $Ifgdr $$Ifa$gdrkd"#$$Ifl4kF0 ( A$ t0*6    44 lap2r2t2z22&3pddUU $Ifgdr $$Ifa$gdrkd#$$Ifl4F0 (A$ t0*6    44 la&3(3.34333pddUU $Ifgdr $$Ifa$gdrkd$$$Ifl4F0 (A$ t0*6    44 la3344d44pddUU $Ifgdr $$Ifa$gdrkdW%$$Ifl4F0 (A$ t0*6    44 la44446pddU $Ifgdr $$Ifa$gdrkd&$$Ifl4F0 (A$ t0*6    44 la6666j77pg[LL $Ifgdr $$Ifa$gdr $Ifgdrkd&$$Ifl4F0 (A$ t0*6    44 la7778h89j9pddUUU $Ifgdr $$Ifa$gdrkd'$$Ifl4F0 ( A$ t0*6    44 laj9l9n9t9 :|:pddUU $Ifgdr $$Ifa$gdrkdC($$Ifl4F0 (A$ t0*6    44 la|:~::::x;pddUU $Ifgdr $$Ifa$gdrkd($$Ifl4F0 (A$ t0*6    44 lax;z;|;;<pddU $Ifgdr $$Ifa$gdrkd)$$Ifl4F0 (A$ t0*6    44 laz;|;;<,<.<<<===F>J>N>T>X>>>???B@@@@@AA,B2BCCCCCFDJDPDDDDJELEREEEEFFJFPFFFGG0GBGDGGGGGGGHHHHHHHHXIII hT(hT(hT(hrmHsHh.m5mH sH hT(h x5mH sH hT(hV5hGhG5 hT(hrhT(hr5I<<<<J==pddUU $Ifgdr $$Ifa$gdrkdt*$$Ifl4F0 (A$ t0*6    44 la====\>>pg[LL $Ifgdr $$Ifa$gdr $Ifgdrkd/+$$Ifl4F0 (A$ t0*6    44 la>>>>T??pddUU $Ifgdr $$Ifa$gdrkd+$$Ifl4F0 ( A$ t0*6    44 la????B@@pddUU $Ifgdr $$Ifa$gdrkd,$$Ifl4F0 (A$ t0*6    44 la@@@@LAApddUU $Ifgdr $$Ifa$gdrkd`-$$Ifl4F0 (A$ t0*6    44 laAAAA*BpddU $Ifgdr $$Ifa$gdrkd.$$Ifl4F0 (A$ t0*6    44 la*B,B2B8BBCCpddUUU $Ifgdr $$Ifa$gdrkd.$$Ifl4F0 (A$ t0*6    44 laCCCCHDpg[L $Ifgdr $$Ifa$gdr $Ifgdrkd/$$Ifl4F0 (A$ t0*6    44 laHDJDPDVDDpddU $Ifgdr $$Ifa$gdrkdL0$$Ifl4F0 ( A$ t0*6    44 laDDDDJEpddU $Ifgdr $$Ifa$gdrkd1$$Ifl4F0 (A$ t0*6    44 laJELEREXEEpddU $Ifgdr $$Ifa$gdrkd1$$Ifl4F0 (A$ t0*6    44 laEEEEHFpddU $Ifgdr $$Ifa$gdrkd}2$$Ifl4F0 (A$ t0*6    44 laHFJFPFVFFpddU $Ifgdr $$Ifa$gdrkd83$$Ifl4F0 (A$ t0*6    44 laFFFFGpddU $Ifgdr $$Ifa$gdrkd3$$Ifl4F0 (A$ t0*6    44 laGG GGGpddR$ $Ifa$gdr $$Ifa$gdrkd4$$Ifl4F0 (A$ t0*6    44 laGGGGGpg[L $Ifgdr $$Ifa$gdr $Ifgdrkdi5$$Ifl4F0 (A$ t0*6    44 laGGGHHHHHHphhhh\\\ $$Ifa$gdr$a$gdrkd)6$$Ifl4F0 ( A $ t0*6    44 laHHHHIoccT $Ifgdr $$Ifa$gdrkd6$$IflF0 (W $ t0*6    44 laIIIIIlJpg[LL $Ifgdr $$Ifa$gdr $Ifgdrkd7$$Ifl4F0 (W $ t0*6    44 laIIIIIInJrJJJKKMMMMNNOO`PbPPQQQ.R2R.S0SSSTTUUpVrVtWzWrXtXZY`YtZvZv[|[B\D\J\t]v]^^ ^^^^^`_f___````zaaaacctcvcccd~dddddfeheffhT(hV5hT(hrmHsH hT(hrhT(hr5WlJnJrJvJJpddU $Ifgdr $$Ifa$gdrkdU8$$Ifl4F0 ( W $ t0*6    44 laJJJJhKKpg[LL $Ifgdr $$Ifa$gdr $Ifgdrkd9$$Ifl4F0 (W $ t0*6    44 laKKKK L|LMpddUUU $Ifgdr $$Ifa$gdrkd9$$Ifl4F0 ( W $ t0*6    44 laMMMM\MMpg[DD 0$If^`0gdr $$Ifa$gdr $Ifgdrkd:$$Ifl4F0 (W $ t0*6    44 laMMMM$$Ifl4F0 ( W $ t0*6    44 laQQQQ,Rpg[L $Ifgdr $$Ifa$gdr $Ifgdrkd>$$Ifl4F0 (W $ t0*6    44 la,R.R2R8RR,SpddUU $Ifgdr $$Ifa$gdrkd?$$Ifl4F0 ( W $ t0*6    44 la,S.S0S6SSpg[L $Ifgdr $$Ifa$gdr $Ifgdrkd^@$$Ifl4F0 (W $ t0*6    44 laSSSSFTTpddMM 0$If^`0gdr $$Ifa$gdrkdA$$Ifl4F0 ( W $ t0*6    44 laTTTUUpg[L $Ifgdr $$Ifa$gdr $IfgdrkdA$$Ifl4F0 (W $ t0*6    44 laUUUUUnVpddMM 0$If^`0gdr $$Ifa$gdrkdB$$Ifl4F0 ( W $ t0*6    44 lanVpVrVxVVrWpg[LL $Ifgdr $$Ifa$gdr $IfgdrkdJC$$Ifl4F0 (W $ t0*6    44 larWtWzWWXpXpddMM 0$If^`0gdr $$Ifa$gdrkdD$$Ifl4F0 ( W $ t0*6    44 lapXrXtXzXXXYpg[LL $Ifgdr $$Ifa$gdr $IfgdrkdD$$Ifl4F0 (W $ t0*6    44 laXYZY`YfYYrZpddMM 0$If^`0gdr $$Ifa$gdrkd{E$$Ifl4F0 ( W $ t0*6    44 larZtZvZ|Z[t[pg[LL $Ifgdr $$Ifa$gdr $Ifgdrkd6F$$Ifl4F0 (W $ t0*6    44 lat[v[|[[[@\pddMM 0$If^`0gdr $$Ifa$gdrkdF$$Ifl4F0 ( W $ t0*6    44 la@\B\D\J\t]pg[L $Ifgdr $$Ifa$gdr $IfgdrkdG$$Ifl4F0 (W $ t0*6    44 lat]v]|]]^pddU $Ifgdr $$Ifa$gdrkdgH$$Ifl4F0 ( W $ t0*6    44 la^^ ^^^neYJ $Ifgdr $$Ifa$gdr $Ifgdrkd"I$$Ifl4F0 (W $ t0*6    44 la^^^^^pddU $Ifgdr $$Ifa$gdrkdI$$Ifl4F0 ( W $ t0*6    44 la^^^^^_pg[L $Ifgdr $$Ifa$gdr $IfgdrkdJ$$Ifl4F0 (W $ t0*6    44 la^_`_f_l__pddU $Ifgdr $$Ifa$gdrkdWK$$Ifl4F0 ( W $ t0*6    44 la____`pddU $Ifgdr $$Ifa$gdrkdL$$Ifl4F0 (W $ t0*6    44 la```$`f``pddMM 0$If^`0gdr $$Ifa$gdrkdL$$Ifl4F0 (W $ t0*6    44 la````xapddU $Ifgdr $$Ifa$gdrkdM$$Ifl4F0 (W $ t0*6    44 laxazaaaanbbS $Ifgdr $$Ifa$gdrkdCN$$Ifl4F0 (W $ t0*6    44 laaaaavb cpddUU $Ifgdr $$Ifa$gdrkdO$$Ifl4F0 (W $ t0*6    44 la ccccrcpddU $Ifgdr $$Ifa$gdrkdO$$Ifl4F0 (W $ t0*6    44 larctcvc|ccnbbS $Ifgdr $$Ifa$gdrkdxP$$Ifl4F0 (W $ t0*6    44 lacccc~dnbbP$ $Ifa$gdr $$Ifa$gdrkd7Q$$Ifl4jF0 (W $ t0*6    44 la~dddddpg[L $Ifgdr $$Ifa$gdr $IfgdrkdQ$$Ifl4F0 (W $ t0*6    44 ladddd edepddUU $Ifgdr $$Ifa$gdrkdR$$Ifl4F0 ( W  $ t0*6    44 ladefeheneebffneYJJJ $Ifgdr $$Ifa$gdr $IfgdrkdvS$$Ifl4(F0 (W $ t0*6    44 lafffff~gnbbKK 0$If^`0gdr $$Ifa$gdrkd5T$$Ifl4jF0 ( W $ t0*6    44 la~ggggg,hpg[L5 0$If^`0gdr $Ifgdr $$Ifa$gdr $IfgdrkdT$$Ifl4F0 (W $ t0*6    44 lafgg.h4hiiiijjNkTkkkllmm n&nnnoozp|pqqrrzst t"t"upvrvtvwwxx2y8y>z@zFzD{F{L{D}F}L}}}}>@F \^d(4FҬ֬ܬh.mhr5mH sH h.m5mH sH hT(hV5UhT(hr5 hT(hrS,h.h4h:hhipddUU $Ifgdr $$Ifa$gdrkdU$$Ifl4F0 ( W $ t0*6    44 laiii$iiipg[L5 0$If^`0gdr $Ifgdr $$Ifa$gdr $IfgdrkdjV$$Ifl4F0 (W $ t0*6    44 laiiiiNjjpddUU $Ifgdr $$Ifa$gdrkd%W$$Ifl4F0 ( W $ t0*6    44 lajjjjkLkpg[LL $Ifgdr $$Ifa$gdr $IfgdrkdW$$Ifl4F0 (W $ t0*6    44 laLkNkTkZkkpddU $Ifgdr $$Ifa$gdrkdX$$Ifl4F0 ( W $ t0*6    44 lakkkklllneYJJJ $Ifgdr $$Ifa$gdr $IfgdrkdVY$$Ifl4F0 (W $ t0*6    44 lallll mnbbS $Ifgdr $$Ifa$gdrkdZ$$Ifl4VF0 ( W $ t0*6    44 la mmmmmmnnbbSSS $Ifgdr $$Ifa$gdrkdZ$$Ifl4wF0 (W $ t0*6    44 lan n&n,npnnpddMM 0$If^`0gdr $$Ifa$gdrkd[$$Ifl4F0 (W $ t0*6    44 lannnn`oopddUU $Ifgdr $$Ifa$gdrkdN\$$Ifl4F0 (W $ t0*6    44 laoooopxppddUU $Ifgdr $$Ifa$gdrkd ]$$Ifl4F0 (W $ t0*6    44 laxpzp|ppppqqpg[LLL $Ifgdr $$Ifa$gdr $Ifgdrkd]$$Ifl4F0 (W $ t0*6    44 laqqqq.rrpddUU $Ifgdr $$Ifa$gdrkd^$$Ifl4F0 ( W $ t0*6    44 larrrrrFsxspddUUU $Ifgdr $$Ifa$gdrkd:_$$Ifl4F0 (W $ t0*6    44 laxszssstpddU $Ifgdr $$Ifa$gdrkd_$$Ifl4F0 (W $ t0*6    44 lat t"t(tt upddUU $Ifgdr $$Ifa$gdrkd`$$Ifl4F0 (W $ t0*6    44 la u"u(u.uupvpddUU $Ifgdr $$Ifa$gdrkdka$$Ifl4F0 (W $ t0*6    44 lapvrvtvzvvHwwwpg[DDDD 0$If^`0gdr $$Ifa$gdr $Ifgdrkd&b$$Ifl4F0 (W $ t0*6    44 lawwwwNxxpddMM 0$If^`0gdr $$Ifa$gdrkdb$$Ifl4F0 ( W $ t0*6    44 laxxxx0ypddU $Ifgdr $$Ifa$gdrkdc$$Ifl4F0 (W $ t0*6    44 la0y2y8y>yyz@zFzzD{pddUU $Ifgdr $$Ifa$gdrkde$$Ifl4F0 (W $ t0*6    44 laD{F{L{R{{f|B}pddMM> $Ifgdr 0$If^`0gdr $$Ifa$gdrkde$$Ifl4F0 (W $ t0*6    44 laB}D}F}L}}pg[L $Ifgdr $$Ifa$gdr $Ifgdrkdf$$Ifl4F0 (W $ t0*6    44 la}}}}`~<pddMM 0$If^`0gdr $$Ifa$gdrkdGg$$Ifl4F0 ( W $ t0*6    44 la<>@FpddU $Ifgdr $$Ifa$gdrkdh$$Ifl4F0 (W $ t0*6    44 lati ch. 3569NX6: Hon thin k thut nhy xa kiu  n thn .70TL4: Kim tra th lc: Chy 30m XPC 3671NX7: n K thut nhy xa kiu"n thn"72NX8: Phng php t chc trng ti mn nhy xa.3773Kim tra hc k II nhy xa kiu  n thn  . (5)74 LP 12 (37 tun/nm hc) (HK I: 19 tun x 2 tit = 38 tit. HK II: 18 tun x 2 tit = 36 tit. C nm: 74 tit) TunTitNi dung11LT1: - Khi nim v ngh)a ca vic tp luyn sc mnh.  Lp phiu kho st 2LT2: - Phng php pht trin sc mnh.23C1: - Di chuyn bc lt. - Tng cu (nhp 1)   tn cng bng mu bn chn.4BC1: - Chuyn bng cao tay bng hai tay. - m bng; Chuyn bc hai.35C2: - Di chuyn bc lt. - Tng cu nhp 1 -  tn cng bng mu bn chn; u tp.6BC2: Chuyn bng cao tay bng hai tay; m bng; Chuyn bc hai.47C3: - Tng  git cu nhp 1  tn cng bng mu bn chn. - u tp; Lut  cu.8BC3: m bng; Chuyn bc hai.59C4: - Tng  git cu nhp 1  tn cng bng mu bn chn. - u tp; Lut  cu.10BC4: - p bng chnh din theo phng ly . - Chuyn bc hai; Gii thiu lut.611C5: - Tng  git cu nhp 1  tn cng bng mu bn chn. - u tp.12BC5: - Chuyn bc hai; p bng chnh din theo phng ly . - Gii thiu lut; u tp.713C6: Kim tra 15 pht KT tng  git cu nhp 1  tn cng bng mu bn chn. (1)14BC6: - p bng chnh din theo phng ly . - Nhy chn bng; u tp.815TD1: Bi TDN 10 ng tc (N): Hc ng tc 1 n 3. Bi TDPTC 50 ng tc (Nam):Hc ng tc t 1 n 10. 16BC7: - Nhy chn bng. - p bng chnh din theo phng ly ; u tp917TD2: Bi TDN (N): n ng tc 1 n 3. Hc ng tc 4 n 5. Bi TDPTC (Nam): ng ng tc 1 n 10. Hc /t 11 n 30.18BC8: Mt s bi tp phi hp; Nhy chn bng; u tp.1019TD3: Bi TDN (N): n ng tc 1 n 5. Hc ng tc 6 n 7. Bi TDPTC 50(Nam): n ng tc 1n 30. Hc /t t 31 n 5020BC9: Mt s bi tp phi hp; u tp.1121TD4: Bi TDN (N): n ng tc t 1 n 7. Hc ng tc 8 n 9. Bi TDPTC 50(Nam): n ng tc t 1 n 50. 22BC10: Kim tra1tit: - KT Chuyn bng bc 2 (N). (2) - p bng chnh din theo phng ly  (Nam)1223TD5: Bi TDN (N): n ng tc 1 n 9. Hc ng tc 10 Bi TDPTC (Nam): n Bi TDPTC 50 ng tc. 24TS1: - Trao nhn tn gy (ti ch v chy chm). - Chy lp li vi tc  cao (2 - 3 ln x 30m).1325TD6: - Hon thin Bi TDN 10 ng tc (N). - Hon thin Bi TDPTC 50 ng tc (Nam) .26TS2: - Trao nhn tn gy (ti ch v chy chm). - Chy lp li vi tc  cao (2 - 3 ln x 30m).1427TD7: KT 15 pht bi TDN 10 /t N - bi TDPTC 50 /t Nam (3)28TS3: -Trao - nhn gy trong khu vc 20m quy nh vi vch bo chun - Mt s im trong Lut in kinh (phn tip sc).1529TS4: - Trao - nhn gy trong khu vc 20m quy nh vi vch bo chun - Mt s im trong Lut in kinh (phn tip sc).30B1: - Dn bng bng m trong bn chn. - Dn bng bng m ngoi bn chn; Dn bng bng mu bn chn. 1631TS5: Phi hp trao - nhn tn gy ton i.32B2: Phi hp dn bng m trong, m ngoi bn chn.1733TS6: Hon thin k thut chy tip sc (4x40m).34B3: - Phi hp dn bng m trong, m ngoi bn chn. - Gii thiu lut1835n k thut chy tip sc (4x40m).36Phng php t chc trng ti mn chy Tip sc.1937Kim tra Hc k I: K thut chy tip sc (4x40m) (4)382039B4: -  bng bng mu bn chn. - Phi hp dn bng m trong, m ngoi bn chn. - Gii thiu lut; u tp.40CL1: nh cu thp thun tay; nh cu trn u (cao su). CB1: Luyn tp chy bn.2141B5: -  bng bng mu bn chn. - Dn bng lun phin bng m trong, m ngoi v mu bn chn. - Gii thiu lut; u tp.42CL2: nh cu thp thun tay; nh cu trn u (cao su). CB2: Luyn tp chy bn.2243B6: -  bng bng mu bn chn. - Dn bng lun phin bng m trong, m ngoi v mu bn chn. - u tp.44CL3: nh cu cao thun tay; Lut cu lng; u tp. CB3: Luyn tp chy bn.2345B7: nh u bng trn gia; u tp.46CL4: - nh cu cao thun tay; u tp. CB4: Luyn tp chy bn.2447B8: nh u bng trn gia; u tp.48CL5: nh cu cao tri tay; Gii thiu lut; u tp. CB5: Luyn tp chy bn.2549B9: - nh u bng trn gia; u tp. - Gii thiu lut.50CL6: nh cu cao tri tay; u tp. CB6: Luyn tp chy bn. 2651B10: Kim tra 15 pht  bng bng mu bn chn, nh u bng gia trn. (1)52CL7: Mt s chin thut; u tp. CB7: Luyn tp chy bn.2753NX1: - Tp m phng ng tc trn khng. - Tp m phng ng tc chn gim, ng tc chn lng.54CL8: Mt s chin thut; Lut Cu lng; u tp. CB8: Luyn tp chy bn. 2855NX2: Chy  (1 - 3 bc) - gim nhy - trn khng - tip t.56CL9: nh cu cao thun tay; nh cu cao tri tay; u tp. CB9: Luyn tp chy bn.2957NX3: - Chy  (1 - 3 bc) - gim nhy - trn khng - tip t. - Tr chi58CL10: Kim tra 1tit KT nh cu cao thun tay hoc tri tay. (2) CB10: Luyn tp chy bn.3059NX4: - Tp hon chnh k thut nhy xa kiu  n thn . - Mt s bi tp pht trin th lc.60CL11: Kim tra 1tit KT nh cu cao thun tay hoc tri tay (TT) . (2) CB1: Luyn tp chy bn. 3161NX5: - Tp hon chnh k thut nhy xa kiu  n thn . - Tr chi.62CB12: Hon thin KT chy bn. Lut thi u v PP trng ti3263NX6: - Tp hon chnh k thut nhy xa kiu  n thn . - Tr chi. 64CB13: Kim tra 15 pht chy bn (3) ( Nam c ly 1000m; N 500m.Tnh thi gian ) 3365NX7: - Tp hon chnh k thut nhy xa kiu  n thn . - Gii thiu lut.66TL1: Kim tra th lc, ni dung: Chy ty sc 5 pht.3467NX8: - Hon thin k thut nhy xa kiu  n thn . - Gii thiu lut.68TL2: Kim tra th lc ni dung: Nm nga gp thn. 3569TL3: Kim tra th lc, ni dung: Bt xa ti ch.70TL4:Kim tra th lc, ni dung: Chy 30m Xut pht cao.3671NX9: n K thut nhy xa kiu"n thn". 72NX10: Phng php t chc trng ti mn nhy xa. 3773Kim tra hc k II: K thut nhy xa kiu"n thn" (4)74 S GIO DC V O TO QUNG NAM PHN PHI CHNG TRNH MN GDQP+AN LP 10 (37 tun/nm hc) (HK I: 19 tun x 1 tit = 19 tit. HK II: 18 tun x1 tit = 18 tit. C nm: 37 tit) TunTitNi dung11Lch s nh gic gi nc ca dn tc Vit Nam.22Truyn thng v vang ca dn tc ta trong s nghip nh gic gi nc (mc 1, 2 SGK).33Truyn thng v vang ca dn tc ta trong s nghip nh gic gi nc (mc 3, 4 SGK).44Truyn thng v vang ca dn tc ta trong s nghip nh gic gi nc (mc 5, 6 SGK.55Lch s Qun i nhn dn Vit Nam.66Truyn thng Qun i nhn dn Vit Nam (mc 1, 2, 3 SGK).77Truyn thng Qun i nhn dn Vit Nam (mc 4, 5, 6 SGK).88Lch s Cng an nhn dn Vit Nam.99Tuyn thng Cng an nhn dn Vit Nam.1010Kim tra 1 tit l thuyt (cc ni dung  hc  HK I lp 10)1111ng tc nghim, ngh, quay ti ch v cho. Luyn tp.1212+ ng tc i u, ng li, i chn khi ang i u; ng tc gim chn, ng li, i chn khi ang gim chn. + ng tc gim chn chuyn thnh i u v ngc li. Luyn tp.1313ng tc tin, li, qua phi, qua tri, ngi xung, ng dy; ng tc chy u, ng li. Luyn tp.1414Luyn tp i ngi tng ngi khng sng.1515i hnh tiu i hng ngang.1616i hnh tiu i hng dc.1717Tin, li, qua phi, qua tri; Gin i hnh, thu i hnh; Ra khi hng v v tr.1818n i ngi tng ngi khng sng1919Kim tra hc k I: i ngi tng ngi khng sng2020Luyn tp i hnh tiu i 1,2 hng ngang; 1,2 hng dc; Tin, li, qua phi, qua tri; Gin i hnh, thu i hnh.2121i hnh trung i hng ngang.2222i hnh trung i hng dc.2323Luyn tp i ngi tiu i, trung i.2424Hiu bit c bn v ma ty.2525Tc hi ca ma ty v nguyn nhn dn n nghin ma ty.2626Du hiu nhn bit hc sinh nghin ma ty v trch nhim ca hc sinh trong phng chng ma ty.2727Du hiu nhn bit hc sinh nghin ma ty v trch nhim ca hc sinh trong phng chng ma ty (tt).2828Bom, n v cch phng trnh.2929Thin tai, tc hi ca chng v cch phng trnh.3030Kim tra 1 tit l thuyt(cc ni dung  hc  HK II lp 10)3131Cp cu ban u cc tai nn thng thng (mc t 1-> 5 - SGK).3232Cp cu ban u cc tai nn thng thng (mc t 6-> 8 - SGK). Bng vt thng (mc t 1-3 - SGK).3333Quan st gio vin thc hin ng tc bng mu.3434Luyn tp bng vt thng (mc 4 - SGK).3535Luyn tp bng vt thng (mc 4 - SGK).3636n i ngi n v - Bng vt thng.3737Kim tra HKII: i ngi n v - Bng vt thng. LP 11 (37 tun/nm hc) (HK I: 19 tun x 1 tit = 19 tit. HK II: 18 tun x1 tit = 18 tit. C nm: 37 tit) TunTitNi dung11i ngi tiu i.22i ngi trung i. 33S cn thit ban hnh Lut NVQS, gii thiu khi qut v Lut.44Nhng quy nh chung, chun b cho thanh nin nhp ngi.55Phc v ti ngi trong thi bnh, x l cc vi phm Lut NVQS66Trch nhim ca hc sinh.77Lnh th quc gia. 88Ch quyn lnh th quc gia, ni dung ch quyn lnh th quc gia.99Khi nim bin gii quc gia, xc nh bin gii quc gia Vit Nam.1010Mt s quan im ca ng v Nh nc v bo v bin gii quc gia. V tr ngh)a ca vic xy dng v qun l, bo v bin gii quc gia.1111Ni dung, bin php xy dng v qun l, bo v bin gii. Trch nhim ca Cng dn.1212Kim tra 1 tit l thuyt(cc ni dung  hc  HK I lp 11)1313+ Gii thiu mt s lu n Vit Nam (mc I). + Quy tc s dng v qun l lu n (mc II).1414T th ng tc ng nm lu n (mc III).1515Nm lu n xa trng ch (mc IV).1616Sng tiu lin AK (mc I).1717+ Sng trng CKC (mc II). + Quy tc s dng v bo qun sng, n (mc III).1818n ng tc nm lu n xa trng ch. 1919Kim tra hc k I: Nm lu n xa trng ch.2020+ Cu to sng tiu lin AK, sng trng CKC v n K56. + Tho, lp sng tiu lin AK v sng trng CKC.2121+ Cu to sng tiu lin AK, sng trng CKC v n K56. + Tho, lp sng tiu lin AK v sng trng CKC.2222K thut cp cu v chuyn thng (l thuyt).2323K thut cp cu v chuyn thng (thc hnh).2424K thut cp cu v chuyn thng (thc hnh).2525K thut cp cu v chuyn thng (thc hnh).2626K thut cp cu v chuyn thng (thc hnh).2727Kim tra thc hnh (Tho lp sng tiu lin AK).2828Mt s ni dung c bn v l thuyt bn.2929+ ng tc bn ti ch ca sng tiu lin AK v CKC. + Luyn tp.3030+ Tp ngm chm v ngm trng, chm. + Luyn tp: tp xoay vng 2 ni dung: ngm chm - ng tc bn ti ch Sng tiu lin AK v sng trng CKC3131Luyn tp cc ni dung: + Tp ngm chm + Tp ngm trng, chm.3232 + Tp bn mc tiu c nh + Luyn tp: Ly ng ngm (ng ngm cht)3333Tp bn mc tiu c nh theo iu kin bi tp.3434Tp bn mc tiu c nh theo iu kin bi tp.3535Tp bn mc tiu c nh theo iu kin bi tp.3636n ng tc nm bn.3737Kim tra hc k II: ng tc nm bn. LP 12 (37 tun/nm hc) (HK I: 19 tun x 1 tit = 19 tit. HK II: 18 tun x1 tit = 18 tit. C nm: 37 tit) TunTitNi dung11i ngi tiu i22i ngi tiu i33T tng ch o ca ng thc hin nhim v QP- AN trong tnh hnh mi.44Ni dung v bin php xy dng nn quc phng ton dn, an ninh nhn dn.55Ni dung v bin php xy dng nn quc phng ton dn, an ninh nhn dn.66Ni dung v bin php xy dng nn quc phng ton dn, an ninh nhn dn.77Trch nhim ca hc sinh trong xy dng nn QP ton dn, an ninh nhn dn.88Nh trng Qun i v tuyn sinh o to.99Nh trng Cng an v tuyn sinh o to.1010Kim tra 1 tit l thuyt (cc ni dung  hc  HK I lp 12)1111Lut S) quan QND Vit Nam 1212Lut S) quan QND Vit Nam 1313Lut Cng an nhn dn.1414Trch nhim ca HS THPT tham gia xy dng i ngi s) quan qun i, Cng an.1515 ngh)a, yu cu ng tc i khom, chy khom.1616ng tc b, l. Luyn tp.1717Luyn tp ng tc i khom, chy khom; ng tc b, l. 1818n ng tc i khom, chy khom; ng tc b, l.1919Kim tra hc k I: ng tc i khom, chy khom; ng tc b, l.2020ng tc trn, vt tin, dng li. Luyn tp.2121Luyn tp, hi thao.2222Luyn tp, hi thao.2323Nhng vn  chung v a hnh, a vt.2424Cch li dng a hnh, a vt.2525Kim tra thc hnh: + ng tc trn, vt tin, dng li. + Li dng a hnh, a vt.2626Qun i nhn dn Vit Nam. 2727Qun i nhn dn Vit Nam.2828Cng an nhn dn Vit Nam.2929S hnh thnh v pht trin cng tc phng khng nhn dn.3030Mt s vn  c bn v cng tc phng khng nhn dn trong tnh hnh mi.3131Mt s vn  c bn v cng tc phng khng nhn dn trong tnh hnh mi.3232Mt s vn  c bn v cng tc phng khng nhn dn trong tnh hnh mi.3333Nhng vn  chung v an ninh quc gia.3434Nhng vn  chung v an ninh quc gia.3535Hc sinh vi nhim v bo v an ninh quc gia.3636n tp ni dung l thuyt hc k II3737Kim tra HKII: L thuyt (cc ni dung  hc HKII lp 12) PHNG GIO DC TRUNG HC     PAGE  PAGE 10 pddU $Ifgdr $$Ifa$gdrkdh$$Ifl4F0 (W $ t0*6    44 la \pddU $Ifgdr $$Ifa$gdrkdxi$$Ifl4F0 (W $ t0*6    44 la\^djpddU $Ifgdr $$Ifa$gdrkd3j$$Ifl4F0 (W $ t0*6    44 laƫ&pddU $Ifgdr $$Ifa$gdrkdj$$Ifl4F0 (W $ t0*6    44 la&(.4ҬpddR$ $Ifa$gdr $$Ifa$gdrkdk$$Ifl4F0 (W $ t0*6    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